3.141 \(\int \text{csch}(a+b x) \text{csch}(c+b x) \, dx\)

Optimal. Leaf size=36 \[ \frac{\text{csch}(a-c) \log (\sinh (b x+c))}{b}-\frac{\text{csch}(a-c) \log (\sinh (a+b x))}{b} \]

[Out]

-((Csch[a - c]*Log[Sinh[a + b*x]])/b) + (Csch[a - c]*Log[Sinh[c + b*x]])/b

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Rubi [A]  time = 0.0237326, antiderivative size = 36, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {5645, 3475} \[ \frac{\text{csch}(a-c) \log (\sinh (b x+c))}{b}-\frac{\text{csch}(a-c) \log (\sinh (a+b x))}{b} \]

Antiderivative was successfully verified.

[In]

Int[Csch[a + b*x]*Csch[c + b*x],x]

[Out]

-((Csch[a - c]*Log[Sinh[a + b*x]])/b) + (Csch[a - c]*Log[Sinh[c + b*x]])/b

Rule 5645

Int[Csch[(a_.) + (b_.)*(x_)]*Csch[(c_) + (d_.)*(x_)], x_Symbol] :> Dist[Csch[(b*c - a*d)/b], Int[Coth[a + b*x]
, x], x] - Dist[Csch[(b*c - a*d)/d], Int[Coth[c + d*x], x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[b^2 - d^2, 0]
&& NeQ[b*c - a*d, 0]

Rule 3475

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin{align*} \int \text{csch}(a+b x) \text{csch}(c+b x) \, dx &=-(\text{csch}(a-c) \int \coth (a+b x) \, dx)+\text{csch}(a-c) \int \coth (c+b x) \, dx\\ &=-\frac{\text{csch}(a-c) \log (\sinh (a+b x))}{b}+\frac{\text{csch}(a-c) \log (\sinh (c+b x))}{b}\\ \end{align*}

Mathematica [A]  time = 0.220831, size = 28, normalized size = 0.78 \[ -\frac{\text{csch}(a-c) (\log (\sinh (a+b x))-\log (\sinh (b x+c)))}{b} \]

Antiderivative was successfully verified.

[In]

Integrate[Csch[a + b*x]*Csch[c + b*x],x]

[Out]

-((Csch[a - c]*(Log[Sinh[a + b*x]] - Log[Sinh[c + b*x]]))/b)

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Maple [B]  time = 0.035, size = 79, normalized size = 2.2 \begin{align*} 2\,{\frac{\ln \left ({{\rm e}^{2\,bx+2\,a}}-{{\rm e}^{2\,a-2\,c}} \right ){{\rm e}^{a+c}}}{b \left ({{\rm e}^{2\,a}}-{{\rm e}^{2\,c}} \right ) }}-2\,{\frac{\ln \left ({{\rm e}^{2\,bx+2\,a}}-1 \right ){{\rm e}^{a+c}}}{b \left ({{\rm e}^{2\,a}}-{{\rm e}^{2\,c}} \right ) }} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csch(b*x+a)*csch(b*x+c),x)

[Out]

2/b/(exp(2*a)-exp(2*c))*ln(exp(2*b*x+2*a)-exp(2*a-2*c))*exp(a+c)-2/b/(exp(2*a)-exp(2*c))*ln(exp(2*b*x+2*a)-1)*
exp(a+c)

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Maxima [B]  time = 1.15714, size = 180, normalized size = 5. \begin{align*} -\frac{2 \, e^{\left (a + c\right )} \log \left (e^{\left (-b x - a\right )} + 1\right )}{b{\left (e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )}\right )}} - \frac{2 \, e^{\left (a + c\right )} \log \left (e^{\left (-b x - a\right )} - 1\right )}{b{\left (e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )}\right )}} + \frac{2 \, e^{\left (a + c\right )} \log \left (e^{\left (-b x\right )} + e^{c}\right )}{b{\left (e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )}\right )}} + \frac{2 \, e^{\left (a + c\right )} \log \left (e^{\left (-b x\right )} - e^{c}\right )}{b{\left (e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)*csch(b*x+c),x, algorithm="maxima")

[Out]

-2*e^(a + c)*log(e^(-b*x - a) + 1)/(b*(e^(2*a) - e^(2*c))) - 2*e^(a + c)*log(e^(-b*x - a) - 1)/(b*(e^(2*a) - e
^(2*c))) + 2*e^(a + c)*log(e^(-b*x) + e^c)/(b*(e^(2*a) - e^(2*c))) + 2*e^(a + c)*log(e^(-b*x) - e^c)/(b*(e^(2*
a) - e^(2*c)))

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Fricas [B]  time = 2.14778, size = 491, normalized size = 13.64 \begin{align*} -\frac{2 \,{\left ({\left (\cosh \left (-a + c\right ) - \sinh \left (-a + c\right )\right )} \log \left (\frac{2 \,{\left (\cosh \left (-a + c\right ) \sinh \left (b x + c\right ) - \cosh \left (b x + c\right ) \sinh \left (-a + c\right )\right )}}{\cosh \left (b x + c\right ) \cosh \left (-a + c\right ) -{\left (\cosh \left (-a + c\right ) + \sinh \left (-a + c\right )\right )} \sinh \left (b x + c\right ) + \cosh \left (b x + c\right ) \sinh \left (-a + c\right )}\right ) -{\left (\cosh \left (-a + c\right ) - \sinh \left (-a + c\right )\right )} \log \left (\frac{2 \, \sinh \left (b x + c\right )}{\cosh \left (b x + c\right ) - \sinh \left (b x + c\right )}\right )\right )}}{b \cosh \left (-a + c\right )^{2} - 2 \, b \cosh \left (-a + c\right ) \sinh \left (-a + c\right ) + b \sinh \left (-a + c\right )^{2} - b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)*csch(b*x+c),x, algorithm="fricas")

[Out]

-2*((cosh(-a + c) - sinh(-a + c))*log(2*(cosh(-a + c)*sinh(b*x + c) - cosh(b*x + c)*sinh(-a + c))/(cosh(b*x +
c)*cosh(-a + c) - (cosh(-a + c) + sinh(-a + c))*sinh(b*x + c) + cosh(b*x + c)*sinh(-a + c))) - (cosh(-a + c) -
sinh(-a + c))*log(2*sinh(b*x + c)/(cosh(b*x + c) - sinh(b*x + c))))/(b*cosh(-a + c)^2 - 2*b*cosh(-a + c)*sinh
(-a + c) + b*sinh(-a + c)^2 - b)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \operatorname{csch}{\left (a + b x \right )} \operatorname{csch}{\left (b x + c \right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)*csch(b*x+c),x)

[Out]

Integral(csch(a + b*x)*csch(b*x + c), x)

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Giac [B]  time = 1.20016, size = 147, normalized size = 4.08 \begin{align*} \frac{2 \, e^{\left (a + c\right )} \log \left (\frac{{\left | -{\left | e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )} \right |} + 2 \, e^{\left (2 \, b x + 2 \, a + 2 \, c\right )} - e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )} \right |}}{{\left |{\left | e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )} \right |} + 2 \, e^{\left (2 \, b x + 2 \, a + 2 \, c\right )} - e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )} \right |}}\right )}{b{\left | e^{\left (2 \, a\right )} - e^{\left (2 \, c\right )} \right |}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)*csch(b*x+c),x, algorithm="giac")

[Out]

2*e^(a + c)*log(abs(-abs(e^(2*a) - e^(2*c)) + 2*e^(2*b*x + 2*a + 2*c) - e^(2*a) - e^(2*c))/abs(abs(e^(2*a) - e
^(2*c)) + 2*e^(2*b*x + 2*a + 2*c) - e^(2*a) - e^(2*c)))/(b*abs(e^(2*a) - e^(2*c)))