Optimal. Leaf size=52 \[ \frac{1}{2} i \text{PolyLog}\left (2,e^{2 i x}\right )-\text{li}(x)+\frac{i x^2}{2}-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x)) \]
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Rubi [A] time = 0.0615273, antiderivative size = 52, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 6, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1., Rules used = {2549, 3717, 2190, 2279, 2391, 2298} \[ \frac{1}{2} i \text{PolyLog}\left (2,e^{2 i x}\right )-\text{li}(x)+\frac{i x^2}{2}-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x)) \]
Antiderivative was successfully verified.
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Rule 2549
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 2298
Rubi steps
\begin{align*} \int \log (\log (x) \sin (x)) \, dx &=x \log (\log (x) \sin (x))-\int \left (x \cot (x)+\frac{1}{\log (x)}\right ) \, dx\\ &=x \log (\log (x) \sin (x))-\int x \cot (x) \, dx-\int \frac{1}{\log (x)} \, dx\\ &=\frac{i x^2}{2}+x \log (\log (x) \sin (x))-\text{li}(x)+2 i \int \frac{e^{2 i x} x}{1-e^{2 i x}} \, dx\\ &=\frac{i x^2}{2}-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x))-\text{li}(x)+\int \log \left (1-e^{2 i x}\right ) \, dx\\ &=\frac{i x^2}{2}-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x))-\text{li}(x)-\frac{1}{2} i \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i x}\right )\\ &=\frac{i x^2}{2}-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x))-\text{li}(x)+\frac{1}{2} i \text{Li}_2\left (e^{2 i x}\right )\\ \end{align*}
Mathematica [A] time = 0.0307747, size = 47, normalized size = 0.9 \[ \frac{1}{2} i \left (x^2+\text{PolyLog}\left (2,e^{2 i x}\right )\right )-\text{li}(x)-x \log \left (1-e^{2 i x}\right )+x \log (\log (x) \sin (x)) \]
Antiderivative was successfully verified.
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Maple [C] time = 0.167, size = 368, normalized size = 7.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.94638, size = 58, normalized size = 1.12 \begin{align*} \frac{1}{2} \,{\left (i \, \pi - 2 \, \log \left (2\right )\right )} x - \frac{1}{2} i \, x^{2} + x \log \left (\log \left (x\right )\right ) -{\rm Ei}\left (\log \left (x\right )\right ) + i \,{\rm Li}_2\left (-e^{\left (i \, x\right )}\right ) + i \,{\rm Li}_2\left (e^{\left (i \, x\right )}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.3886, size = 427, normalized size = 8.21 \begin{align*} x \log \left (\log \left (x\right ) \sin \left (x\right )\right ) - \frac{1}{2} \, x \log \left (\cos \left (x\right ) + i \, \sin \left (x\right ) + 1\right ) - \frac{1}{2} \, x \log \left (\cos \left (x\right ) - i \, \sin \left (x\right ) + 1\right ) - \frac{1}{2} \, x \log \left (-\cos \left (x\right ) + i \, \sin \left (x\right ) + 1\right ) - \frac{1}{2} \, x \log \left (-\cos \left (x\right ) - i \, \sin \left (x\right ) + 1\right ) + \frac{1}{2} i \,{\rm Li}_2\left (\cos \left (x\right ) + i \, \sin \left (x\right )\right ) - \frac{1}{2} i \,{\rm Li}_2\left (\cos \left (x\right ) - i \, \sin \left (x\right )\right ) - \frac{1}{2} i \,{\rm Li}_2\left (-\cos \left (x\right ) + i \, \sin \left (x\right )\right ) + \frac{1}{2} i \,{\rm Li}_2\left (-\cos \left (x\right ) - i \, \sin \left (x\right )\right ) - \logintegral \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \log{\left (\log{\left (x \right )} \sin{\left (x \right )} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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