3.22 \(\int \frac{a m x^m+b n q \log ^{-1+q}(c x^n)}{x (a x^m+b \log ^q(c x^n))^3} \, dx\)

Optimal. Leaf size=22 \[ -\frac{1}{2 \left (a x^m+b \log ^q\left (c x^n\right )\right )^2} \]

[Out]

-1/(2*(a*x^m + b*Log[c*x^n]^q)^2)

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Rubi [A]  time = 0.180028, antiderivative size = 22, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.023, Rules used = {2544} \[ -\frac{1}{2 \left (a x^m+b \log ^q\left (c x^n\right )\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[(a*m*x^m + b*n*q*Log[c*x^n]^(-1 + q))/(x*(a*x^m + b*Log[c*x^n]^q)^3),x]

[Out]

-1/(2*(a*x^m + b*Log[c*x^n]^q)^2)

Rule 2544

Int[((Log[(c_.)*(x_)^(n_.)]^(q_)*(b_.) + (a_.)*(x_)^(m_.))^(p_.)*(Log[(c_.)*(x_)^(n_.)]^(r_.)*(e_.) + (d_.)*(x
_)^(m_.)))/(x_), x_Symbol] :> Simp[(e*(a*x^m + b*Log[c*x^n]^q)^(p + 1))/(b*n*q*(p + 1)), x] /; FreeQ[{a, b, c,
 d, e, m, n, p, q, r}, x] && EqQ[r, q - 1] && NeQ[p, -1] && EqQ[a*e*m - b*d*n*q, 0]

Rubi steps

\begin{align*} \int \frac{a m x^m+b n q \log ^{-1+q}\left (c x^n\right )}{x \left (a x^m+b \log ^q\left (c x^n\right )\right )^3} \, dx &=-\frac{1}{2 \left (a x^m+b \log ^q\left (c x^n\right )\right )^2}\\ \end{align*}

Mathematica [A]  time = 0.0401071, size = 22, normalized size = 1. \[ -\frac{1}{2 \left (a x^m+b \log ^q\left (c x^n\right )\right )^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(a*m*x^m + b*n*q*Log[c*x^n]^(-1 + q))/(x*(a*x^m + b*Log[c*x^n]^q)^3),x]

[Out]

-1/(2*(a*x^m + b*Log[c*x^n]^q)^2)

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Maple [C]  time = 0.184, size = 68, normalized size = 3.1 \begin{align*} -{\frac{1}{2\, \left ( a{x}^{m}+b \left ( \ln \left ( c \right ) +\ln \left ({x}^{n} \right ) -i/2\pi \,{\it csgn} \left ( ic{x}^{n} \right ) \left ( -{\it csgn} \left ( ic{x}^{n} \right ) +{\it csgn} \left ( ic \right ) \right ) \left ( -{\it csgn} \left ( ic{x}^{n} \right ) +{\it csgn} \left ( i{x}^{n} \right ) \right ) \right ) ^{q} \right ) ^{2}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*m*x^m+b*n*q*ln(c*x^n)^(-1+q))/x/(a*x^m+b*ln(c*x^n)^q)^3,x)

[Out]

-1/2/(a*x^m+b*(ln(c)+ln(x^n)-1/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*c*x^n)+csgn(I*c))*(-csgn(I*c*x^n)+csgn(I*x^n)))^q
)^2

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Maxima [B]  time = 2.132, size = 66, normalized size = 3. \begin{align*} -\frac{1}{2 \,{\left (a^{2} x^{2 \, m} + b^{2}{\left (\log \left (c\right ) + \log \left (x^{n}\right )\right )}^{2 \, q} + 2 \, a b e^{\left (m \log \left (x\right ) + q \log \left (\log \left (c\right ) + \log \left (x^{n}\right )\right )\right )}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))/x/(a*x^m+b*log(c*x^n)^q)^3,x, algorithm="maxima")

[Out]

-1/2/(a^2*x^(2*m) + b^2*(log(c) + log(x^n))^(2*q) + 2*a*b*e^(m*log(x) + q*log(log(c) + log(x^n))))

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Fricas [B]  time = 2.04863, size = 116, normalized size = 5.27 \begin{align*} -\frac{1}{2 \,{\left (2 \,{\left (n \log \left (x\right ) + \log \left (c\right )\right )}^{q} a b x^{m} +{\left (n \log \left (x\right ) + \log \left (c\right )\right )}^{2 \, q} b^{2} + a^{2} x^{2 \, m}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))/x/(a*x^m+b*log(c*x^n)^q)^3,x, algorithm="fricas")

[Out]

-1/2/(2*(n*log(x) + log(c))^q*a*b*x^m + (n*log(x) + log(c))^(2*q)*b^2 + a^2*x^(2*m))

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x**m+b*n*q*ln(c*x**n)**(-1+q))/x/(a*x**m+b*ln(c*x**n)**q)**3,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b n q \log \left (c x^{n}\right )^{q - 1} + a m x^{m}}{{\left (a x^{m} + b \log \left (c x^{n}\right )^{q}\right )}^{3} x}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))/x/(a*x^m+b*log(c*x^n)^q)^3,x, algorithm="giac")

[Out]

integrate((b*n*q*log(c*x^n)^(q - 1) + a*m*x^m)/((a*x^m + b*log(c*x^n)^q)^3*x), x)