### 3.1016 $$\int \frac{1}{(d+e x)^2 (c d^2+2 c d e x+c e^2 x^2)^2} \, dx$$

Optimal. Leaf size=17 $-\frac{1}{5 c^2 e (d+e x)^5}$

[Out]

-1/(5*c^2*e*(d + e*x)^5)

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Rubi [A]  time = 0.0047017, antiderivative size = 17, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 30, $$\frac{\text{number of rules}}{\text{integrand size}}$$ = 0.1, Rules used = {27, 12, 32} $-\frac{1}{5 c^2 e (d+e x)^5}$

Antiderivative was successfully veriﬁed.

[In]

Int[1/((d + e*x)^2*(c*d^2 + 2*c*d*e*x + c*e^2*x^2)^2),x]

[Out]

-1/(5*c^2*e*(d + e*x)^5)

Rule 27

Int[(u_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[u*Cancel[(b/2 + c*x)^(2*p)/c^p], x] /; Fr
eeQ[{a, b, c}, x] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 32

Int[((a_.) + (b_.)*(x_))^(m_), x_Symbol] :> Simp[(a + b*x)^(m + 1)/(b*(m + 1)), x] /; FreeQ[{a, b, m}, x] && N
eQ[m, -1]

Rubi steps

\begin{align*} \int \frac{1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2} \, dx &=\int \frac{1}{c^2 (d+e x)^6} \, dx\\ &=\frac{\int \frac{1}{(d+e x)^6} \, dx}{c^2}\\ &=-\frac{1}{5 c^2 e (d+e x)^5}\\ \end{align*}

Mathematica [A]  time = 0.0045773, size = 17, normalized size = 1. $-\frac{1}{5 c^2 e (d+e x)^5}$

Antiderivative was successfully veriﬁed.

[In]

Integrate[1/((d + e*x)^2*(c*d^2 + 2*c*d*e*x + c*e^2*x^2)^2),x]

[Out]

-1/(5*c^2*e*(d + e*x)^5)

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Maple [A]  time = 0.043, size = 16, normalized size = 0.9 \begin{align*} -{\frac{1}{5\,{c}^{2}e \left ( ex+d \right ) ^{5}}} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x+d)^2/(c*e^2*x^2+2*c*d*e*x+c*d^2)^2,x)

[Out]

-1/5/c^2/e/(e*x+d)^5

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Maxima [B]  time = 1.0261, size = 101, normalized size = 5.94 \begin{align*} -\frac{1}{5 \,{\left (c^{2} e^{6} x^{5} + 5 \, c^{2} d e^{5} x^{4} + 10 \, c^{2} d^{2} e^{4} x^{3} + 10 \, c^{2} d^{3} e^{3} x^{2} + 5 \, c^{2} d^{4} e^{2} x + c^{2} d^{5} e\right )}} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(c*e^2*x^2+2*c*d*e*x+c*d^2)^2,x, algorithm="maxima")

[Out]

-1/5/(c^2*e^6*x^5 + 5*c^2*d*e^5*x^4 + 10*c^2*d^2*e^4*x^3 + 10*c^2*d^3*e^3*x^2 + 5*c^2*d^4*e^2*x + c^2*d^5*e)

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Fricas [B]  time = 2.10266, size = 149, normalized size = 8.76 \begin{align*} -\frac{1}{5 \,{\left (c^{2} e^{6} x^{5} + 5 \, c^{2} d e^{5} x^{4} + 10 \, c^{2} d^{2} e^{4} x^{3} + 10 \, c^{2} d^{3} e^{3} x^{2} + 5 \, c^{2} d^{4} e^{2} x + c^{2} d^{5} e\right )}} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(c*e^2*x^2+2*c*d*e*x+c*d^2)^2,x, algorithm="fricas")

[Out]

-1/5/(c^2*e^6*x^5 + 5*c^2*d*e^5*x^4 + 10*c^2*d^2*e^4*x^3 + 10*c^2*d^3*e^3*x^2 + 5*c^2*d^4*e^2*x + c^2*d^5*e)

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Sympy [B]  time = 0.822059, size = 82, normalized size = 4.82 \begin{align*} - \frac{1}{5 c^{2} d^{5} e + 25 c^{2} d^{4} e^{2} x + 50 c^{2} d^{3} e^{3} x^{2} + 50 c^{2} d^{2} e^{4} x^{3} + 25 c^{2} d e^{5} x^{4} + 5 c^{2} e^{6} x^{5}} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)**2/(c*e**2*x**2+2*c*d*e*x+c*d**2)**2,x)

[Out]

-1/(5*c**2*d**5*e + 25*c**2*d**4*e**2*x + 50*c**2*d**3*e**3*x**2 + 50*c**2*d**2*e**4*x**3 + 25*c**2*d*e**5*x**
4 + 5*c**2*e**6*x**5)

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Giac [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(c*e^2*x^2+2*c*d*e*x+c*d^2)^2,x, algorithm="giac")

[Out]

Exception raised: NotImplementedError