Optimal. Leaf size=46 \[ \frac{5}{8} \log \left (x^2+x+2\right )-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{\tan ^{-1}\left (\frac{2 x+1}{\sqrt{7}}\right )}{4 \sqrt{7}} \]
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Rubi [A] time = 0.0592398, antiderivative size = 46, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {1594, 1628, 634, 618, 204, 628} \[ \frac{5}{8} \log \left (x^2+x+2\right )-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{\tan ^{-1}\left (\frac{2 x+1}{\sqrt{7}}\right )}{4 \sqrt{7}} \]
Antiderivative was successfully verified.
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Rule 1594
Rule 1628
Rule 634
Rule 618
Rule 204
Rule 628
Rubi steps
\begin{align*} \int \frac{1+x^2+x^3}{2 x^2+x^3+x^4} \, dx &=\int \frac{1+x^2+x^3}{x^2 \left (2+x+x^2\right )} \, dx\\ &=\int \left (\frac{1}{2 x^2}-\frac{1}{4 x}+\frac{3+5 x}{4 \left (2+x+x^2\right )}\right ) \, dx\\ &=-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{1}{4} \int \frac{3+5 x}{2+x+x^2} \, dx\\ &=-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{1}{8} \int \frac{1}{2+x+x^2} \, dx+\frac{5}{8} \int \frac{1+2 x}{2+x+x^2} \, dx\\ &=-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{5}{8} \log \left (2+x+x^2\right )-\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,1+2 x\right )\\ &=-\frac{1}{2 x}+\frac{\tan ^{-1}\left (\frac{1+2 x}{\sqrt{7}}\right )}{4 \sqrt{7}}-\frac{\log (x)}{4}+\frac{5}{8} \log \left (2+x+x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0253046, size = 46, normalized size = 1. \[ \frac{5}{8} \log \left (x^2+x+2\right )-\frac{1}{2 x}-\frac{\log (x)}{4}+\frac{\tan ^{-1}\left (\frac{2 x+1}{\sqrt{7}}\right )}{4 \sqrt{7}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 36, normalized size = 0.8 \begin{align*} -{\frac{1}{2\,x}}-{\frac{\ln \left ( x \right ) }{4}}+{\frac{5\,\ln \left ({x}^{2}+x+2 \right ) }{8}}+{\frac{\sqrt{7}}{28}\arctan \left ({\frac{ \left ( 1+2\,x \right ) \sqrt{7}}{7}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.41136, size = 47, normalized size = 1.02 \begin{align*} \frac{1}{28} \, \sqrt{7} \arctan \left (\frac{1}{7} \, \sqrt{7}{\left (2 \, x + 1\right )}\right ) - \frac{1}{2 \, x} + \frac{5}{8} \, \log \left (x^{2} + x + 2\right ) - \frac{1}{4} \, \log \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.9602, size = 128, normalized size = 2.78 \begin{align*} \frac{2 \, \sqrt{7} x \arctan \left (\frac{1}{7} \, \sqrt{7}{\left (2 \, x + 1\right )}\right ) + 35 \, x \log \left (x^{2} + x + 2\right ) - 14 \, x \log \left (x\right ) - 28}{56 \, x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.149009, size = 46, normalized size = 1. \begin{align*} - \frac{\log{\left (x \right )}}{4} + \frac{5 \log{\left (x^{2} + x + 2 \right )}}{8} + \frac{\sqrt{7} \operatorname{atan}{\left (\frac{2 \sqrt{7} x}{7} + \frac{\sqrt{7}}{7} \right )}}{28} - \frac{1}{2 x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.06356, size = 49, normalized size = 1.07 \begin{align*} \frac{1}{28} \, \sqrt{7} \arctan \left (\frac{1}{7} \, \sqrt{7}{\left (2 \, x + 1\right )}\right ) - \frac{1}{2 \, x} + \frac{5}{8} \, \log \left (x^{2} + x + 2\right ) - \frac{1}{4} \, \log \left ({\left | x \right |}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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