LAB #6 report. MAE 106. UCI. Winter 2005

Nasser Abbasi, LAB time: Thursday 2/17/2005 6 PM

Answer 1.

part(a)


Figure

Free diagram for model (2) is the following (assuming m1 is moving to right faster than m2)
Figure

$\ $Now derive equations. Take right to be positive.

For m1:

MATH

For m2:

MATH

part(b)

determine transfer function MATH

Write the dynamic equations in matrix form, we get

MATH

Above can be written as

MATH

Hence , taking laplace transform we get

MATH

Now, MATH

MATH

MATH

Hence MATH

Now MATH

But for the above, MATH

MATH

Hence

MATH

i.e.MATH

and MATH

part(c)

Let $s=j\omega $ hence MATH

$x_{1}$ will not move whenMATH

but MATH implies MATH. i.e. MATH. But this is the sum of 2 positive quantities. So it is only possible to sum to zero only when each quantity itself is zero. i.e. MATH

But for non zero $\omega $ this means that $c_{3}=0$. But $c_{3}$ (the samping) is not zero, since we do have damping in the systems, hence it is not possible thatMATH . In otherwords, there will not be an isolation fequency, and $x_{1}$ will always be non-zero.

But if $c_{3}$ is very small, then $c_{3}\omega =0$ and in this case MATH when MATH or when MATH

Answer 2.

part(a)

Need to derive a mathematical model. First step is to make a block diagram as follows.
Figure


Figure

There are 2 motions. One rotational about the center of mass, and one translation, up and down.

Free body diagrams are
Figure

Now the equation of motion for the rotational motion is MATH

But MATH

Hence we get for small $\theta $, using MATH

MATH

For the translation motion, $F=ma$

hence MATH

part (b)

Write the above in matrix form, we get

MATH

Take laplace transform we get

Let MATH

MATH

MATH

Hence above matrix equation can be written as

$M\ddot{A}+KA=0$

Take laplace transform, we get

$Ms^{2}A+KA=0$

MATH where $I$ is the $2\times 2$ identity matrix.

let $s=j\omega $ we get

MATH

multiply both side by $M^{-1}$ we get

MATH

i.e.

MATH

Which is what we are required to show.

Part (c)

MATH

$L_{1}=4ft$

$L_{2}=5ft$

$m=2500lb$

MATH

MATH

MATH

MATH

Hence MATH

Hence the natural frequency for the linear (translation) motion is

1.7889 rad/sec
, and for the rotational motion it is
4.2162 rad/sec
.